Electron movements may change formal charges. You
can quickly write the new formal charges, however, if you pay attention
to arrow locations and follow these simple rules:
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- Tail atom
The arrowtail atom loses an electron. Add +1 to its
charge.
- Head atom
The arrowhead atom gains an electron. Add -1 to its
charge.
- Tail+Head atom
When a drawing contains more than one arrow, some atoms
will be sandwiched between two arrows. A sandwiched atom
is a tail atom for one arrow and a head atom for a second
arrow, and its electron count does not change. Do not
change its charge.
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Most electron movements are represented by chains
of arrows. A chain consists of a tail atom (D), a head atom (A),
and some tail+head atoms (Z) in between. There is always a net transfer
of one electron from the tail to the head (from D to A), but the
other atoms do not gain or lose electrons. (Note: organic chemists
commonly use D and A to represent generalized electron donor
and electron acceptor atoms.)
Some electron movements are represented by rings of
arrows. A true ring contains only tail+head atoms, and no changes
in formal charge occur.
Examples
The following reaction shows the shortest chain possible
(one arrow). One electron shifts from O (tail) to C (head atom),
so we add +1 to the formal charge on O and -1 to the charge on C.
The next example shows two resonance forms, again
related by the shortest chain of arrows possible: one arrow. Again,
we add +1 to the tail atom's (C) charge and -1 to the head atom's
(O) charge.
Is it completely obvious that O is the tail atom and
not C? Both atoms are part of the origin (CO bond), but only
O is part of the destination (lone pair). The bond atom that is
not part of the destination (C) is always the tail atom.
Here is another example. The origin is a bond, but
you should be able to pick out the tail atom (C) by finding the
atom that is not part of the destination. The formal charges immediately
follow from our rules: C is the tail (add +1), Br is the destination
(add -1).
The next example shows a reaction with three arrows.
Can you see that the arrows form a chain? The tail is O (add +1)
and the head is Br (add -1). The other atoms are tail+head atoms
and their charges do not change.
In some cases, a tail+head atom might start out with
a positive or negative charge. This does not matter, however. As
long as the atom is a tail+head atom, its formal charge will not
change.
Review problems
Take some time to practice what you have learned on
this page. Work each problem in two steps. First, identify the tail
and head atoms (if these atoms are present) in the BEFORE drawing
and say what their formal charges will be in the AFTER drawing.
Second, make a complete drawing of the AFTER formula and compare
it with my answer.
#1.
tail
& head answers | AFTER
answer
#2.
tail
& head answers | AFTER
answer
#3.
tail
& head answers | AFTER
answer
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